Integrand size = 30, antiderivative size = 190 \[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\frac {a^2 c^3 \log (\cos (e+f x)) \tan (e+f x)}{f \sqrt {a+a \sec (e+f x)} \sqrt {c-c \sec (e+f x)}}-\frac {a^2 c^2 \sqrt {c-c \sec (e+f x)} \tan (e+f x)}{f \sqrt {a+a \sec (e+f x)}}-\frac {a^2 c (c-c \sec (e+f x))^{3/2} \tan (e+f x)}{2 f \sqrt {a+a \sec (e+f x)}}+\frac {a^2 (c-c \sec (e+f x))^{5/2} \tan (e+f x)}{3 f \sqrt {a+a \sec (e+f x)}} \]
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Time = 0.48 (sec) , antiderivative size = 190, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {3994, 3991, 3990, 3556} \[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\frac {a^2 c^3 \tan (e+f x) \log (\cos (e+f x))}{f \sqrt {a \sec (e+f x)+a} \sqrt {c-c \sec (e+f x)}}-\frac {a^2 c^2 \tan (e+f x) \sqrt {c-c \sec (e+f x)}}{f \sqrt {a \sec (e+f x)+a}}-\frac {a^2 c \tan (e+f x) (c-c \sec (e+f x))^{3/2}}{2 f \sqrt {a \sec (e+f x)+a}}+\frac {a^2 \tan (e+f x) (c-c \sec (e+f x))^{5/2}}{3 f \sqrt {a \sec (e+f x)+a}} \]
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Rule 3556
Rule 3990
Rule 3991
Rule 3994
Rubi steps \begin{align*} \text {integral}& = \frac {a^2 (c-c \sec (e+f x))^{5/2} \tan (e+f x)}{3 f \sqrt {a+a \sec (e+f x)}}+a \int \sqrt {a+a \sec (e+f x)} (c-c \sec (e+f x))^{5/2} \, dx \\ & = -\frac {a^2 c (c-c \sec (e+f x))^{3/2} \tan (e+f x)}{2 f \sqrt {a+a \sec (e+f x)}}+\frac {a^2 (c-c \sec (e+f x))^{5/2} \tan (e+f x)}{3 f \sqrt {a+a \sec (e+f x)}}+(a c) \int \sqrt {a+a \sec (e+f x)} (c-c \sec (e+f x))^{3/2} \, dx \\ & = -\frac {a^2 c^2 \sqrt {c-c \sec (e+f x)} \tan (e+f x)}{f \sqrt {a+a \sec (e+f x)}}-\frac {a^2 c (c-c \sec (e+f x))^{3/2} \tan (e+f x)}{2 f \sqrt {a+a \sec (e+f x)}}+\frac {a^2 (c-c \sec (e+f x))^{5/2} \tan (e+f x)}{3 f \sqrt {a+a \sec (e+f x)}}+\left (a c^2\right ) \int \sqrt {a+a \sec (e+f x)} \sqrt {c-c \sec (e+f x)} \, dx \\ & = -\frac {a^2 c^2 \sqrt {c-c \sec (e+f x)} \tan (e+f x)}{f \sqrt {a+a \sec (e+f x)}}-\frac {a^2 c (c-c \sec (e+f x))^{3/2} \tan (e+f x)}{2 f \sqrt {a+a \sec (e+f x)}}+\frac {a^2 (c-c \sec (e+f x))^{5/2} \tan (e+f x)}{3 f \sqrt {a+a \sec (e+f x)}}-\frac {\left (a^2 c^3 \tan (e+f x)\right ) \int \tan (e+f x) \, dx}{\sqrt {a+a \sec (e+f x)} \sqrt {c-c \sec (e+f x)}} \\ & = \frac {a^2 c^3 \log (\cos (e+f x)) \tan (e+f x)}{f \sqrt {a+a \sec (e+f x)} \sqrt {c-c \sec (e+f x)}}-\frac {a^2 c^2 \sqrt {c-c \sec (e+f x)} \tan (e+f x)}{f \sqrt {a+a \sec (e+f x)}}-\frac {a^2 c (c-c \sec (e+f x))^{3/2} \tan (e+f x)}{2 f \sqrt {a+a \sec (e+f x)}}+\frac {a^2 (c-c \sec (e+f x))^{5/2} \tan (e+f x)}{3 f \sqrt {a+a \sec (e+f x)}} \\ \end{align*}
Time = 0.83 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.46 \[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\frac {a^2 c^3 \left (2+6 \log (\cos (e+f x))+6 \sec (e+f x)+3 \sec ^2(e+f x)-2 \sec ^3(e+f x)\right ) \tan (e+f x)}{6 f \sqrt {a (1+\sec (e+f x))} \sqrt {c-c \sec (e+f x)}} \]
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Time = 2.10 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.87
method | result | size |
default | \(-\frac {a \sqrt {-c \left (\sec \left (f x +e \right )-1\right )}\, \left (\sec \left (f x +e \right )-1\right )^{2} c^{2} \sqrt {a \left (\sec \left (f x +e \right )+1\right )}\, \left (6 \cos \left (f x +e \right )^{3} \ln \left (-\cot \left (f x +e \right )+\csc \left (f x +e \right )+1\right )+6 \cos \left (f x +e \right )^{3} \ln \left (-\cot \left (f x +e \right )+\csc \left (f x +e \right )-1\right )-6 \cos \left (f x +e \right )^{3} \ln \left (\frac {2}{\cos \left (f x +e \right )+1}\right )+\cos \left (f x +e \right )^{3}+6 \cos \left (f x +e \right )^{2}+3 \cos \left (f x +e \right )-2\right ) \csc \left (f x +e \right )}{6 f \left (\cos \left (f x +e \right )-1\right )^{2}}\) | \(166\) |
risch | \(-\frac {a \,c^{2} \sqrt {\frac {a \left ({\mathrm e}^{i \left (f x +e \right )}+1\right )^{2}}{1+{\mathrm e}^{2 i \left (f x +e \right )}}}\, \sqrt {\frac {c \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )^{2}}{1+{\mathrm e}^{2 i \left (f x +e \right )}}}\, \left (6 i {\mathrm e}^{5 i \left (f x +e \right )}+3 \,{\mathrm e}^{6 i \left (f x +e \right )} f x +6 i {\mathrm e}^{i \left (f x +e \right )}+6 \,{\mathrm e}^{6 i \left (f x +e \right )} e +9 \,{\mathrm e}^{4 i \left (f x +e \right )} f x +6 i {\mathrm e}^{4 i \left (f x +e \right )}+18 \,{\mathrm e}^{4 i \left (f x +e \right )} e +9 \,{\mathrm e}^{2 i \left (f x +e \right )} f x +9 i {\mathrm e}^{4 i \left (f x +e \right )} \ln \left (1+{\mathrm e}^{2 i \left (f x +e \right )}\right )+6 i {\mathrm e}^{2 i \left (f x +e \right )}+9 i {\mathrm e}^{2 i \left (f x +e \right )} \ln \left (1+{\mathrm e}^{2 i \left (f x +e \right )}\right )+3 i \ln \left (1+{\mathrm e}^{2 i \left (f x +e \right )}\right ) {\mathrm e}^{6 i \left (f x +e \right )}+4 i {\mathrm e}^{3 i \left (f x +e \right )}+3 i \ln \left (1+{\mathrm e}^{2 i \left (f x +e \right )}\right )+18 \,{\mathrm e}^{2 i \left (f x +e \right )} e +3 f x +6 e \right )}{3 \left (1+{\mathrm e}^{2 i \left (f x +e \right )}\right )^{2} \left ({\mathrm e}^{i \left (f x +e \right )}+1\right ) \left ({\mathrm e}^{i \left (f x +e \right )}-1\right ) f}\) | \(339\) |
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Time = 0.33 (sec) , antiderivative size = 467, normalized size of antiderivative = 2.46 \[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\left [-\frac {{\left (7 \, a c^{2} \cos \left (f x + e\right )^{2} + a c^{2} \cos \left (f x + e\right ) - 2 \, a c^{2}\right )} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} \sin \left (f x + e\right ) - 3 \, {\left (a c^{2} \cos \left (f x + e\right )^{3} + a c^{2} \cos \left (f x + e\right )^{2}\right )} \sqrt {-a c} \log \left (\frac {a c \cos \left (f x + e\right )^{4} - {\left (\cos \left (f x + e\right )^{3} + \cos \left (f x + e\right )\right )} \sqrt {-a c} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} \sin \left (f x + e\right ) + a c}{2 \, \cos \left (f x + e\right )^{2}}\right )}{6 \, {\left (f \cos \left (f x + e\right )^{3} + f \cos \left (f x + e\right )^{2}\right )}}, -\frac {{\left (7 \, a c^{2} \cos \left (f x + e\right )^{2} + a c^{2} \cos \left (f x + e\right ) - 2 \, a c^{2}\right )} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} \sin \left (f x + e\right ) - 6 \, {\left (a c^{2} \cos \left (f x + e\right )^{3} + a c^{2} \cos \left (f x + e\right )^{2}\right )} \sqrt {a c} \arctan \left (\frac {\sqrt {a c} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right )}{a c \cos \left (f x + e\right )^{2} + a c}\right )}{6 \, {\left (f \cos \left (f x + e\right )^{3} + f \cos \left (f x + e\right )^{2}\right )}}\right ] \]
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Timed out. \[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1356 vs. \(2 (170) = 340\).
Time = 0.48 (sec) , antiderivative size = 1356, normalized size of antiderivative = 7.14 \[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\text {Too large to display} \]
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\[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\int { {\left (a \sec \left (f x + e\right ) + a\right )}^{\frac {3}{2}} {\left (-c \sec \left (f x + e\right ) + c\right )}^{\frac {5}{2}} \,d x } \]
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Timed out. \[ \int (a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^{5/2} \, dx=\int {\left (a+\frac {a}{\cos \left (e+f\,x\right )}\right )}^{3/2}\,{\left (c-\frac {c}{\cos \left (e+f\,x\right )}\right )}^{5/2} \,d x \]
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